In the Problem Analysis page of this example, several equations are given as graphics, as conventional mathematical layout is not supported by HTML. These equations are described in this section.

The air pressure equations divide the height domain into three regions, and give a different equation for each region. The equation for the region 83245 < h is:

p(h) = 51.97 ((T + 459.7)/389.98)^{-11.388}

The equation for the region 36152 < h < 82345 is:

p(h) = 473.1e^{1.73 - .000048h}

The equation for the region h < 36152 is:

p(h) = 2116 ((T + 459.7)/518.6)^{5.256}

The air temperature equations divide the height into the same three regions as the air pressure equations, and give a different equation for each region. The equation for the region 83245 < h is:

T(h) = -205.05 + 0.00164h

The equation for the region 36152 < h < 82345 is:

T(h) = -70

The equation for the region h < 36152 is:

T(h) = 59 - 0.00356h

The equation for the speed of sound is:

a(T) = sqrt (γRT)

where “sqrt” indicates the square root of its argument.

Click here to return to the problem analysis of the pumpkin drop example.

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Copyright © 2002 Brian Hetrick

Page last updated 27 January 2002.

Tutorial

Building Blocks I

Control Flow II

Basic I/O

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A First Program

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Pumpkins

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Building Blocks II

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